Question

write the electron configuration of an atom of the element highlighted in this outline of the periodic table: hint: you do not need to know the name or symbol of the highlighted element!

Explanation:

Step1: Determine the noble - gas core

The element is in period 6. The noble - gas core for period 6 is \([Xe]\) (xenon has the electron configuration \(1s^{2}2s^{2}2p^{6}3s^{2}3p^{6}3d^{10}4s^{2}4p^{6}4d^{10}5s^{2}5p^{6}\)).

Step2: Fill the remaining orbitals

The element is in the s - block of period 6. After the \([Xe]\) core, the next orbitals to fill are \(6s\). Since it is the first element in the s - block of period 6, the electron configuration is \([Xe]6s^{1}\)

Answer:

\([Xe]6s^{1}\)