Question

write the complete ground-state electron configuration of be²⁺. for multi-digit superscripts or coefficients, use each number in succession.

Explanation:

Step1: Determine the atomic number of Be

The atomic number of Be (beryllium) is \(4\). So, a neutral Be atom has \(4\) electrons.

Step2: Consider the ion charge

\(Be^{2 + }\) has lost \(2\) electrons. So, the number of electrons in \(Be^{2 + }\) is \(4- 2=2\).

Step3: Write the electron configuration

The electron configuration is based on filling orbitals in the order \(1s\), \(2s\), \(2p\) etc. With \(2\) electrons, the configuration is \(1s^{2}\).

Answer:

\(1s^{2}\)