Question

1. write the chemical equation for the burning of methane here:ch₄ + 2o₂ → co₂ + 2h₂o5. what does the arrow represent in a chemical equation?it seperates the reactants from the products and shows the direction in which the reaction proceeds6. what does the number 2 represent in front of the water and oxygen molecules?2 oxygen molecules and 2 water molecules are involved in the reaction7. if the above equation for the burning of methane obeys the law of conservation of matter,how many of each element do you have at the start, and the end, of the reaction?a. carbon:____b. oxygen:__c. hydrogen:____

Explanation:

Step1: Analyze Carbon

• Reactants: In \(CH_4\), there is \(1\) carbon atom.
• Products: In \(CO_2\), there is \(1\) carbon atom.

Step2: Analyze Oxygen

• Reactants: In \(2O_2\), there are \(2\times2 = 4\) oxygen atoms.
• Products: In \(CO_2\) there are \(2\) oxygen atoms and in \(2H_2O\) there are \(2\times1= 2\) oxygen atoms. Total \(2 + 2=4\) oxygen atoms.

Step3: Analyze Hydrogen

• Reactants: In \(CH_4\), there are \(4\) hydrogen atoms.
• Products: In \(2H_2O\), there are \(2\times2 = 4\) hydrogen atoms.

Answer:

a. Carbon: \(1\) (start), \(1\) (end)
b. Oxygen: \(4\) (start), \(4\) (end)
c. Hydrogen: \(4\) (start), \(4\) (end)