Question

which z - values correspond to the bottom 99% of the standard normal distribution? round your answer to the nearest thousandth. z <

Explanation:

Step1: Use the standard normal distribution table (z - table)

We need to find \(z\) such that \(P(Z < z)=0.99\).

Step2: Look up the value in the z - table

Looking up the value \(0.99\) in the body of the standard normal distribution table. The closest value to \(0.99\) in the standard normal table. The \(z\) - value corresponding to a cumulative probability of \(0.99\) is approximately \(z = 2.33\) (since for \(z = 2.33\), the cumulative probability \(P(Z<2.33)\approx0.9901\) and for \(z = 2.32\), \(P(Z < 2.32)=0.9898\)).

Answer:

\(z<2.33\)