4. which chemical equation occurred in a closed system?
a. lioh + co₂ → li₂co₃ + h₂o
b. 2lioh + co₂ → li₂co₃ + h₂o
c. lioh + 3co₂ → 2li₂co₃ + h₂o
d. 4lioh + co₂ → li₂co₃ + 2h₂o

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Accepted Answer

# Explanation:
## Step1: Balance the chemical equation
According to the law of conservation of mass, the number of atoms of each element on both sides of the chemical equation should be equal.
For option B:
- Left - hand side: $2$ $Li$ atoms ($2LiOH$), $2$ $O$ atoms ($2LiOH$) + $2$ $O$ atoms ($CO_{2}$)=$4$ $O$ atoms, $2$ $H$ atoms ($2LiOH$), $1$ $C$ atom ($CO_{2}$).
- Right - hand side: $2$ $Li$ atoms ($Li_{2}CO_{3}$), $3$ $O$ atoms ($Li_{2}CO_{3}$)+$1$ $O$ atom ($H_{2}O$)=$4$ $O$ atoms, $2$ $H$ atoms ($H_{2}O$), $1$ $C$ atom ($Li_{2}CO_{3}$).

## Step2: Check other options
- Option A: Unbalanced $Li$ and $O$ atoms.
- Option C: Unbalanced $Li$ and $C$ atoms.
- Option D: Unbalanced $Li$ and $O$ atoms.

# Answer:
B. $2LiOH + CO_{2}\to Li_{2}CO_{3}+H_{2}O$

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QUESTION IMAGE

Question

Explanation:

Step1: Balance the chemical equation

Step2: Check other options

Answer: