Question

when rolling a six - sided die, what is the probability of rolling a number greater than 3?

Explanation:

Step1: Determine total outcomes

The total number of possible outcomes when rolling a six - sided die is 6 (the numbers 1, 2, 3, 4, 5, 6), so $n(S)=6$.

Step2: Determine favorable outcomes

The numbers greater than 3 on a six - sided die are 4, 5, 6. So the number of favorable outcomes $n(A)=3$.

Step3: Calculate probability

The probability formula is $P(A)=\frac{n(A)}{n(S)}$. Substituting the values, we get $P(A)=\frac{3}{6}=\frac{1}{2}$.

Answer:

$\frac{1}{2}$