Question

what volume, in ml, of 0.63 m hno3 can be prepared by diluting 341 ml of 5.25 m stock solution? report your answer to one place after the decimal point.

Explanation:

Step1: Use the dilution formula

The dilution formula is \(C_1V_1 = C_2V_2\), where \(C_1\) is the initial concentration, \(V_1\) is the initial volume, \(C_2\) is the final concentration, and \(V_2\) is the final volume.
Given \(C_1 = 5.25\space M\), \(V_1=341\space mL\), \(C_2 = 0.63\space M\). We need to find \(V_2\).
From \(C_1V_1 = C_2V_2\), we can express \(V_2=\frac{C_1V_1}{C_2}\).

Step2: Substitute the values

Substitute the values into the formula: \(V_2=\frac{5.25\times341}{0.63}\).
First, calculate \(5.25\times341 = 5.25\times(300 + 40+1)=5.25\times300+5.25\times40 + 5.25\times1=1575+210 + 5.25=1790.25\).
Then, \(\frac{1790.25}{0.63}=\frac{179025}{63}\).
\(179025\div63 = 2841.666\cdots\)

Answer:

\(2841.7\space mL\)