Question

what is the volume of 16.7 g of oxygen gas at stp?
23.4 l
11.7 l
23.8 l
374 l
what volume does 0.0894 mol of hydrogen gas occupy at stp?
2.00 l
0.00399 l
0.991 l
1.98 l

Explanation:

Step1: Calculate moles of oxygen gas

The molar mass of \(O_2\) is \(M = 32\space g/mol\). Using the formula \(n=\frac{m}{M}\), where \(m = 16.7\space g\). So \(n=\frac{16.7\space g}{32\space g/mol}= 0.521875\space mol\).

Step2: Use molar volume at STP

At STP (Standard Temperature and Pressure), the molar volume of a gas \(V_m=22.4\space L/mol\). Using the formula \(V = n\times V_m\), substitute \(n = 0.521875\space mol\) and \(V_m = 22.4\space L/mol\). So \(V=0.521875\times22.4 = 11.7\space L\).

Step3: Calculate volume of hydrogen gas

For the second question, using the formula \(V=n\times V_m\), where \(n = 0.0894\space mol\) and \(V_m=22.4\space L/mol\). So \(V=0.0894\times22.4 = 1.98\space L\).

Answer:

11.7 L
1.98 L