Question

what is the value of $b(0)$, as defined by the piecewise function below?
$b(x) = \

$$\begin{cases} 2x - 1 & , x \\leq 1 \\\\ 1 & , x > 1 \\end{cases}$$

$

Explanation:

Step1: Determine the applicable piece

Check if \( x = 0 \) satisfies \( x \leq 1 \) or \( x > 1 \). Since \( 0 \leq 1 \), use \( b(x)=2x - 1 \).

Step2: Substitute \( x = 0 \)

Substitute \( x = 0 \) into \( 2x - 1 \): \( 2(0)-1=-1 \).

Answer:

\(-1\)