Question

what type of symmetry does cosine have? even odd no symmetry

Explanation:

A function \( y = f(x) \) is even if \( f(-x)=f(x) \) for all \( x \) in the domain of \( f \). For the cosine function, \( \cos(-x)=\cos(x) \). Also, looking at the graph, it is symmetric about the \( y \) - axis (which is the characteristic of an even function). A function \( y = f(x) \) is odd if \( f(-x)=-f(x) \) for all \( x \) in the domain of \( f \), and \( \cos(-x)
eq-\cos(x) \) (except when \( \cos(x) = 0 \)). Since \( \cos(-x)=\cos(x) \), it does not satisfy the condition for an odd function. And it is not a function with no symmetry as it has \( y \) - axis symmetry.

Answer:

Even