Question

what was the ratio in the formula for iron (ii) oxide? what was the ratio in the formula for iron (iii) oxide? o has -1 charge. o has -2 charge. o has +1 charge.

Explanation:

Step1: Determine iron (II) oxide formula

Iron (II) has a +2 charge ($Fe^{2 + }$), oxygen has a - 2 charge ($O^{2 - }$). To form a neutral compound, the ratio of iron to oxygen is 1:1, and the formula is $FeO$.

Step2: Determine iron (III) oxide formula

Iron (III) has a +3 charge ($Fe^{3+}$), oxygen has a - 2 charge ($O^{2 - }$). Using the criss - cross method to balance the charges, we get the formula $Fe_{2}O_{3}$, and the ratio of iron to oxygen is 2:3.

Answer:

The ratio in the formula for iron (II) oxide is 1:1.
The ratio in the formula for iron (III) oxide is 2:3.