Question

what is the oxidation state for p in h4p2o7? you do not need to include a positive sign for a positive oxidation number.

Explanation:

Step1: Set up the equation

Let the oxidation state of \(P\) be \(x\). In \(H_4P_2O_7\), the oxidation state of \(H\) is \(+ 1\) and of \(O\) is \(-2\). The sum of oxidation states in a neutral compound is \(0\). So, \(4\times(+1)+2x + 7\times(-2)=0\).

Step2: Solve the equation

$$
LATEXBLOCK0
$$

Answer:

\(5\)