Question

what is the net ionic equation for the reaction between aqueous sodium hydroxide and nitric acid?
a.
h+(aq) + oh-(aq) + na+(aq) + no3-(aq) → h2o(l) + nano3(s)
b.
h+(aq) + oh-(aq) + no3-(aq) → h2o(l) + no3-(aq)
c.
h+(aq) + oh-(aq) + na+(aq) → h2o(l) + na+(aq)
d.
h+(aq) + oh-(aq) → h2o(l)

Explanation:

Step1: Write the balanced molecular equation

Sodium hydroxide (\(NaOH\)) reacts with nitric acid (\(HNO_3\)) to form sodium nitrate (\(NaNO_3\)) and water (\(H_2O\)).
\(NaOH(aq)+HNO_3(aq)
ightarrow NaNO_3(aq)+H_2O(l)\)

Step2: Write the total ionic equation

\(Na^+(aq)+OH^-(aq)+H^+(aq)+NO_3^-(aq)
ightarrow Na^+(aq)+NO_3^-(aq)+H_2O(l)\)

Step3: Identify and cancel out the spectator ions

Spectator ions are \(Na^+\) and \(NO_3^-\) as they appear on both sides of the equation.
After canceling them, we get the net ionic equation.

Answer:

D. \(H^{+}(aq)+OH^{-}(aq)\to H_{2}O(l)\)