Question

what is the molarity of a solution made by dissolving 22.5 g of glucose, c₆h₁₂o₆, in 35.5 ml of water. (molar mass of c₆h₁₂o₆ = 180.0 g/mol)
a. 3.52 m
b. 0.634 m
c. 0.197 m
d. 0.125 m
e. 1.85 m

Explanation:

Step1: Calculate moles of glucose

Moles \(n=\frac{\text{mass}}{\text{molar mass}}\). Given mass \(m = 22.5\space g\) and molar mass \(M=180.0\space g/mol\).
\(n=\frac{22.5\space g}{180.0\space g/mol}=0.125\space mol\)

Step2: Convert volume to liters

Volume \(V = 35.5\space mL\). Since \(1\space L=1000\space mL\), \(V=\frac{35.5}{1000}\space L = 0.0355\space L\)

Step3: Calculate molarity

Molarity \(M=\frac{n}{V}\). Substitute \(n = 0.125\space mol\) and \(V=0.0355\space L\)
\(M=\frac{0.125\space mol}{0.0355\space L}\approx3.52\space M\)

Answer:

A. \(3.52\space M\)