Question

what is the missing particle?
144 58 ce* -> ? + 0 0 γ
144 58 ce
144 59 pr
144 57 la

Explanation:

Step1: Analyze the mass number

In a nuclear reaction, the mass number is conserved. The mass number of \(^{144}_{58}\text{Ce}^*\) is \(144\), and the mass number of \(\gamma\) (photon) is \(0\). So the mass number of the missing particle is \(144 - 0=144\).

Step2: Analyze the atomic number

The atomic number is also conserved. The atomic number of \(^{144}_{58}\text{Ce}^*\) is \(58\), and the atomic number of \(\gamma\) is \(0\). So the atomic number of the missing particle is \(58 - 0 = 58\).

Answer:

\(^{144}_{58}\text{Ce}\)