9. a) what does \-\ mean?
b) reactants are found on the ______ side of an equation, producc
______ side.
c) why must all chemical equations be balanced? (state the law of conservation of
mass):
10. a) hydrogen gas reacts with oxygen gas to produce water.
word:
skeleton: ______ + ______ - ______
balance the reaction above!
what type of reaction is this? ______
b) magnesium reacts with calcium iodide to produce magnesium iodide with calcium
word:
skeleton: ______ + ______ - ______
balance the reaction above!
what type of reaction is this? ______
11. balance and write the type of reaction for the following questions:
type of reaction
a) ______ p₄ + ______ o₂ - ______ p₄o₁₀
______
b) ______ fecl₃ + ______ na₂s - ______ nacl + ______ fe₂s₃ ______
c) ______ br₂ + ______ cal₂ - ______ i₂ + ______ cabr₂ ______
d) ______ h₂o - ______ h₂ + ______ o₂ ______

Question

9. a) what does \->\ mean?
b) reactants are found on the ______ side of an equation, producc
______ side.
c) why must all chemical equations be balanced? (state the law of conservation of
mass):
10. a) hydrogen gas reacts with oxygen gas to produce water.
word:
skeleton: ______ + ______ -> ______
balance the reaction above!
what type of reaction is this? ______
b) magnesium reacts with calcium iodide to produce magnesium iodide with calcium
word:
skeleton: ______ + ______ -> ______
balance the reaction above!
what type of reaction is this? ______
11. balance and write the type of reaction for the following questions:
type of reaction
a) ______ p₄ + ______ o₂ -> ______ p₄o₁₀
______
b) ______ fecl₃ + ______ na₂s -> ______ nacl + ______ fe₂s₃ ______
c) ______ br₂ + ______ cal₂ -> ______ i₂ + ______ cabr₂ ______
d) ______ h₂o -> ______ h₂ + ______ o₂ ______

Accepted Answer

# 11. a)
## Step1: Balance oxygen atoms
We have $P_4 + O_2
ightarrow P_4O_{10}$. For oxygen, in $P_4O_{10}$ there are 10 oxygen atoms. In $O_2$, let the coefficient of $O_2$ be $x$. So $2x = 10$, $x = 5$.
The balanced equation is $P_4+5O_2
ightarrow P_4O_{10}$.
This is a **synthesis reaction** (two or more reactants combine to form a single product).

# 11. b)
## Step1: Balance Fe, Cl, Na and S atoms
For $FeCl_3+Na_2S
ightarrow NaCl + Fe_2S_3$
- For Fe: There are 2 Fe atoms in $Fe_2S_3$, so put 2 in front of $FeCl_3$.
- For Cl: $2FeCl_3$ has 6 Cl atoms. So put 6 in front of $NaCl$.
- For Na: $6NaCl$ has 6 Na atoms. So put 3 in front of $Na_2S$.
- For S: $3Na_2S$ has 3 S atoms and $Fe_2S_3$ has 3 S atoms.
The balanced equation is $2FeCl_3 + 3Na_2S
ightarrow 6NaCl+Fe_2S_3$.
This is a **double - displacement reaction** (the positive and negative ions of two ionic compounds exchange places).

# 11. c)
## Step1: Balance Br, Ca and I atoms
For $Br_2+CaI_2
ightarrow I_2+CaBr_2$
- The number of each type of atom (Br: 2, Ca: 1, I: 2) is the same on both sides.
The balanced equation is $Br_2+CaI_2
ightarrow I_2 + CaBr_2$.
This is a **single - displacement reaction** (one element replaces another element in a compound).

# 11. d)
## Step1: Balance H and O atoms
For $H_2O
ightarrow H_2+O_2$
- For O: There are 2 O atoms in $O_2$, so put 2 in front of $H_2O$.
- For H: $2H_2O$ has 4 H atoms. So put 2 in front of $H_2$.
The balanced equation is $2H_2O
ightarrow 2H_2+O_2$.
This is a **decomposition reaction** (a single compound breaks down into two or more simpler substances).

# Answer:
a) $1\ P_4+5\ O_2
ightarrow1\ P_4O_{10}$, synthesis reaction
b) $2\ FeCl_3 + 3\ Na_2S
ightarrow 6\ NaCl+1\ Fe_2S_3$, double - displacement reaction
c) $1\ Br_2+1\ CaI_2
ightarrow1\ I_2 + 1\ CaBr_2$, single - displacement reaction
d) $2\ H_2O
ightarrow 2\ H_2+1\ O_2$, decomposition reaction

Sovi.AI - AI Math Tutor

QUESTION IMAGE

Question

Explanation:

11. a)

Step1: Balance oxygen atoms

11. b)

Step1: Balance Fe, Cl, Na and S atoms

11. c)

Step1: Balance Br, Ca and I atoms

11. d)

Step1: Balance H and O atoms

Answer: