Question

1. what is the concentration of hcl in the final solution when 65 ml of a 6.0 m hcl solution is diluted with pure water to a total volume of 0.15 l?

a) 2.6×103 m b) 14 m c) 2.6 m d) 1.4×10 - 2 m

Explanation:

Step1: Convert the initial volume to liters

The initial volume \( V_1 = 65\space mL=65\times10^{- 3}\space L = 0.065\space L\), the initial concentration \( C_1 = 6.0\space M\), and the final volume \( V_2=0.15\space L\).

Step2: Use the dilution formula \(C_1V_1 = C_2V_2\)

We want to find \(C_2\). Rearranging the formula gives \(C_2=\frac{C_1V_1}{V_2}\).
Substitute the values: \(C_2=\frac{6.0\space M\times0.065\space L}{0.15\space L}\)

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Answer:

C. \(2.6\space M\)