Question

what is the closest bond angle around the central atom in the h₃o⁺ ion? 109.5° 180° 120° 90°

Explanation:

Step1: Determine the electron - pair geometry

The \(H_3O^+\) ion has 4 electron pairs (3 bonding pairs and 1 lone pair) around the central \(O\) atom. According to VSEPR theory, the electron - pair geometry is tetrahedral.

Step2: Consider the effect of lone pair on bond angle

In a tetrahedral electron - pair geometry, the ideal bond angle is \(109.5^{\circ}\). But due to the repulsion from the lone pair, the bond angle is slightly less than \(109.5^{\circ}\), but among the given options, \(109.5^{\circ}\) is the closest.

Answer:

\(109.5^{\circ}\)