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Question
what is the balanced equation for this reaction? hno₂ + nh₄oh → 2hno₂ + nh₄oh → 2nh₄no₂ + h₂o hno₂ + 2nh₄oh → nh₄no₂ + 2h₂o hno₂ + nh₄oh → nh₄no₂ + h₂o
Step1: Count atoms on both sides
For the reaction \(HNO_2+NH_4OH\to\), count \(H\), \(N\), \(O\) atoms.
In \(HNO_2\): \(1\) \(H\), \(1\) \(N\), \(2\) \(O\). In \(NH_4OH\): \(5\) \(H\), \(1\) \(N\), \(1\) \(O\).
On the product side, for \(NH_4NO_2\): \(4\) \(H\), \(2\) \(N\), \(2\) \(O\). For \(H_2O\): \(2\) \(H\), \(1\) \(O\).
Step2: Check balance
In \(HNO_2 + NH_4OH=NH_4NO_2 + H_2O\),
- \(H\): Left side \(1 + 5=6\), Right side \(4+2 = 6\)
- \(N\): Left side \(1 + 1=2\), Right side \(2\)
- \(O\): Left side \(2+1 = 3\), Right side \(2 + 1=3\)
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\(HNO_2+NH_4OH = NH_4NO_2 + H_2O\)