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the weights of a certain dog breed are approximately normally distribut…

Question

the weights of a certain dog breed are approximately normally distributed with a mean of $\mu = 52$ pounds and a standard deviation of $\sigma = 5$ pounds. fill in the indicated boxes. $\mu = 52$ $\sigma = 5$

Explanation:

Step1: Calculate $\mu - 3\sigma$

Given $\mu = 52$ and $\sigma=5$, then $\mu - 3\sigma=52-3\times5=52 - 15 = 37$.

Step2: Calculate $\mu - 2\sigma$

$\mu - 2\sigma=52-2\times5=52 - 10 = 42$.

Step3: Calculate $\mu+2\sigma$

$\mu + 2\sigma=52+2\times5=52 + 10 = 62$.

Step4: Calculate $\mu+3\sigma$

$\mu + 3\sigma=52+3\times5=52 + 15 = 67$.

Answer:

From left - to - right, the values are \(37\), \(42\), \(62\), \(67\).