Question

using the
as\ idea, how many bonds are made in the compound ccl4?
n = 40, a = 32, s = 8

Explanation:

Step1: Apply the formula

The formula using the NAS idea is \( \text{Number of bonds}=\frac{N - A - S}{2}\).

Step2: Substitute the values

Substitute \(N = 40\), \(A = 32\), and \(S = 8\) into the formula: \(\frac{40-32 - 8}{2}\).
First, calculate the numerator: \(40-32-8=0\). Then \(\frac{0}{2}=0\). Wait, no, maybe the formula is \( \text{Number of bonds}=\frac{N - A}{2}\) (if \(S\) is for some other adjustment and in basic bond - counting with \(N\) as total valence electrons if all atoms were noble - gas like (\(N = 8\times5\) for \(CCl_4\) since \(C\) and \(4\) \(Cl\) atoms, \(8\times5 = 40\)), \(A\) as actual valence electrons (\(C:4\), \(Cl:7\times4 = 28\), \(A=4 + 28=32\)). Then \(\frac{40-32}{2}\).
Calculate \(40 - 32=8\), then \(\frac{8}{2}=4\).

Answer:

\(4\)