Question

use the special triangles on the unit circle to determine \\( \theta \\) in degrees when \\( \sin \theta = \frac { \sqrt { 3 } } { 2 } \\). (1 point) 30° 45° 90° 60°

Explanation:

Step1: Recall sine values of special angles

We know that for special angles in the unit - circle:

• $\sin30^{\circ}=\frac{1}{2}$
• $\sin45^{\circ}=\frac{\sqrt{2}}{2}$
• $\sin60^{\circ}=\frac{\sqrt{3}}{2}$
• $\sin90^{\circ} = 1$

Answer:

$60^{\circ}$