Question

use the results from a survey of a simple random sample of 1181 adults. among the 1181 respondents, 91% rated themselves as above average drivers. we want to test the claim that \frac{17}{20} of adults rate themselves as above average drivers. complete parts (a) through (c).
a. identify the actual number of respondents who rated themselves as above average drivers.
(round to the nearest whole number as needed.)

Explanation:

Step1: Convert percentage to decimal

To find the number of respondents, we first convert the percentage \(91\%\) to a decimal. \(91\%=\frac{91}{100} = 0.91\)

Step2: Calculate the number of respondents

We know the total number of respondents \(n = 1181\). The number of respondents who rated themselves as above - average drivers is \(x=n\times p\), where \(p = 0.91\). So \(x=1181\times0.91\)

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Step3: Round to the nearest whole number

Rounding \(1074.71\) to the nearest whole number. Since the decimal part \(0.71\gt0.5\), we round up.

Answer:

\(1075\)