Question

use a graph to solve the inequality.\\(x^2 - x - 12 > 0\\)\
graph the equation \\(y = x^2 - x - 12\\) by plotting points. complete the following table.\

\\(x\\)	\\(-2\\)	\\(-1\\)	\\(0\\)	\\(1\\)	\\(2\\)	\
---	---	---	---	---	---	\
\\(x^2 - x - 12\\)	\\(-6\\)	\\(-10\\)	\\(\square\\)	\\(\square\\)	\\(\square\\)

Explanation:

Step1: Calculate for \( x = 0 \)

Substitute \( x = 0 \) into \( y = x^2 - x - 12 \).
\( y = 0^2 - 0 - 12 = -12 \)

Step2: Calculate for \( x = 1 \)

Substitute \( x = 1 \) into \( y = x^2 - x - 12 \).
\( y = 1^2 - 1 - 12 = 1 - 1 - 12 = -12 \)

Step3: Calculate for \( x = 2 \)

Substitute \( x = 2 \) into \( y = x^2 - x - 12 \).
\( y = 2^2 - 2 - 12 = 4 - 2 - 12 = -10 \)

Answer:

For \( x = 0 \), \( y = -12 \); for \( x = 1 \), \( y = -12 \); for \( x = 2 \), \( y = -10 \)
(So the completed table cells are \(-12\), \(-12\), \(-10\) for \( x = 0, 1, 2 \) respectively)