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use the graph below to fill in each entry of the grid with positive, ne…

Question

use the graph below to fill in each entry of the grid with positive, negative or zero.

Explanation:

Step1: Analyze \( f \)

  • At point \( A \): The \( y - \)coordinate (\( f(A)\)) is below the \( x - \)axis, so \( f(A)<0\) (negative).
  • At point \( B \): The \( y - \)coordinate (\( f(B)\)) is on the \( x - \)axis, so \( f(B) = 0\).
  • At point \( C \): The \( y - \)coordinate (\( f(C)\)) is above the \( x - \)axis, so \( f(C)>0\) (positive).

Step2: Analyze \( f' \)

  • The first - derivative \( f'(x)\) represents the slope of the tangent line.
  • At point \( A \): The function is increasing (slope of the tangent line is positive), so \( f'(A)>0\) (positive).
  • At point \( B \): The function has a local minimum. The slope of the tangent line at a local minimum is \( 0\), so \( f'(B)=0\).
  • At point \( C \): The function is decreasing (slope of the tangent line is negative), so \( f'(C)<0\) (negative).

Step3: Analyze \( f'' \)

  • The second - derivative \( f''(x)\) represents the concavity. If \( f''(x)>0\), the function is concave up; if \( f''(x)<0\), the function is concave down.
  • At point \( A \): The function is concave up (like a cup), so \( f''(A)>0\) (positive).
  • At point \( B \): The function is concave up (since it is a local minimum of a smooth function, and the concavity is the same in the neighborhood of a local minimum for a twice - differentiable function), so \( f''(B)>0\) (positive).
  • At point \( C \): The function is concave down (like a cap), so \( f''(C)<0\) (negative).

Answer:

\( f \)\( f' \)\( f'' \)
\( B \)zerozeropositive
\( C \)positivenegativenegative