Question

use the given conditions to write an equation for the line in point - slope form and general form. passing through (1, - 4) and perpendicular to the line whose equation is x - 8y - 3 = 0 the equation of the line in point - slope form is y + 4 = - 8(x - 1) (type an equation. use integers or fractions for any numbers in the equation.) the equation of the line in general form is \square = 0. (type an expression using x and y as the variables. simplify your answer. use integers or fractions for any numbers in the expression.)

Explanation:

Step1: Start with point-slope form

$y + 4 = -8(x - 1)$

Step2: Expand the right-hand side

$y + 4 = -8x + 8$

Step3: Rearrange to general form

$8x + y - 4 = 0$

Answer:

$8x + y - 4$