Question

use the following balanced equation to answer the questions: 3rb + p → rb₃p there are 3 moles of rb present. the molar mass of rubidium is 85.47 g/mol. what mass of rubidium is present?

Explanation:

Step1: Recall the formula for mass

The formula for mass \(m\) is \(m = n\times M\), where \(n\) is the number of moles and \(M\) is the molar mass.

Step2: Substitute the given values

Given \(n = 3\space mol\) (moles of \(Rb\)) and \(M=85.47\space g/mol\) (molar mass of \(Rb\)).
Substitute into the formula: \(m=3\space mol\times85.47\space g/mol\).

Step3: Calculate the mass

\(m = 3\times85.47=256.41\space g\)

Answer:

\(256.41\space g\)