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QUESTION IMAGE

use the dropdown menus to analyze the zeros in the denominator and dete…

Question

use the dropdown menus to analyze the zeros in the denominator and determine if they correspond to holes or vertical asymptotes. answer attempt 1 out of 2 at x = 8, f has a zero in the denominator and also in the numerator. there is a hole at x = 8 because the multiplicity of the root in the numerator is greater than or equal to less than the multiplicity of the root in the denominator. at x = -2, f has a zero in the numerator.

Explanation:

Step1: Recall Hole and Vertical Asymptote Rules

For a rational function \( f(x)=\frac{N(x)}{D(x)} \), a root \( x = a \) in both numerator and denominator:

  • If multiplicity of \( a \) in \( N(x) \) \( = \) multiplicity in \( D(x) \), there is a hole at \( x = a \).
  • If multiplicity of \( a \) in \( N(x) \) \( < \) multiplicity in \( D(x) \), there is a vertical asymptote at \( x = a \).

Step2: Analyze \( x = 8 \)

At \( x = 8 \), \( f \) has a zero (root) in denominator \( D(x) \) and also in numerator \( N(x) \). For a hole to exist, the multiplicity of the root in numerator must be equal to the multiplicity in denominator.

Step3: Analyze \( x = -2 \)

At \( x = -2 \), \( f \) has a zero in numerator (but no mention of denominator having \( x = -2 \) as a root, or if denominator has it, the multiplicity in numerator is "less than" (since it’s a vertical asymptote or just a zero in numerator; but the dropdown is about numerator vs denominator multiplicity for \( x = 8 \)’s hole). Wait, the first blank: "At \( x = 8 \), \( f \) has a zero in the denominator and also \(\boldsymbol{\text{a zero}}\) in the numerator. There is a hole at \( x = 8 \) because the multiplicity of the root in the numerator is \(\boldsymbol{\text{equal to}}\) the multiplicity of the root in the denominator." The second part about \( x = -2 \): "At \( x = -2 \), \( f \) has a zero in the numerator (and denominator’s multiplicity for \( x = -2 \) is greater, so it’s a vertical asymptote, but the dropdown for the first part is about \( x = 8 \))".

Answer:

First blank: a zero; Second blank: equal to (for the hole condition at \( x = 8 \)).

(Note: The image’s dropdowns: first dropdown for "also in the numerator" should be "a zero", second dropdown for "multiplicity of the root in the numerator is" should be "equal to" the denominator’s multiplicity for a hole.)