Question

use the drawing tool(s) to form the correct answer on the provided graph. draw the graph of function f. f(x) = |x - 3| + 3

Explanation:

Step1: Identify vertex of absolute value

The vertex of $f(x)=|x-h|+k$ is $(h,k)$. For $f(x)=|x-3|+1$, vertex is $(3,1)$.

Step2: Find point for $x<3$

Let $x=0$: $f(0)=|0-3|+1=3+1=4$. Point: $(0,4)$.

Step3: Find point for $x>3$

Let $x=6$: $f(6)=|6-3|+1=3+1=4$. Point: $(6,4)$.

Step4: Draw the two rays

1. Draw a ray from $(3,1)$ through $(0,4)$ (left side, slope 1).
2. Draw a ray from $(3,1)$ through $(6,4)$ (right side, slope -1).

Answer:

The graph is a V-shaped absolute value graph with vertex at $(3,1)$, passing through $(0,4)$ and $(6,4)$, formed by two rays extending from the vertex.