Question

use the chemical equation to answer the question.
br₂(l)+2nai(aq)→i₂(s)+2nabr(aq)
which elements are oxidized and reduced in the reaction?
(1 point)
sodium (na) is oxidized, and bromine (br) is reduced.
iodine (i) is oxidized, and bromine (br) is reduced.
bromine (br) is oxidized, and iodine (i) is reduced.

Explanation:

Step1: Determine oxidation states

• In \(NaI\), the oxidation state of \(I\) is \(- 1\). In \(I_{2}\), the oxidation state of \(I\) is \(0\). So \(I\) loses electrons (oxidation).
• In \(Br_{2}\), the oxidation state of \(Br\) is \(0\). In \(NaBr\), the oxidation state of \(Br\) is \(-1\). So \(Br\) gains electrons (reduction).

Step2: Analyze options

• Sodium (\(Na\)) has an oxidation state of \(+1\) in both \(NaI\) and \(NaBr\), so it is not oxidized or reduced.
• Bromine (\(Br\)) is reduced (as shown in Step 1).
• Iodine (\(I\)) is oxidized (as shown in Step 1).

Answer:

Iodine (I) is oxidized, and bromine (Br) is reduced.