Question

use a calculator to evaluate the function at the indicated values. round your answers to thre
$h(x) = e^{-2x}; \\ \\ h\left(\frac{1}{2}\
ight), h(1.5), h(-1), h(-\pi)$
$h\left(\frac{1}{2}\
ight) = $
$h(1.5) = $
$h(-1) = $
$h(-\pi) = $

Explanation:

Step1: Calculate \(h(\frac{1}{2})\)

Substitute \(x=\frac{1}{2}\): \(h(\frac{1}{2})=e^{-2\times\frac{1}{2}}=e^{-1}\approx0.3679\approx0.368\)

Step2: Calculate \(h(1.5)\)

Substitute \(x=1.5\): \(h(1.5)=e^{-2\times1.5}=e^{-3}\approx0.04979\approx0.050\)

Step3: Calculate \(h(-1)\)

Substitute \(x=-1\): \(h(-1)=e^{-2\times(-1)}=e^{2}\approx7.3891\approx7.389\)

Step4: Calculate \(h(-\pi)\)

Substitute \(x=-\pi\): \(h(-\pi)=e^{-2\times(-\pi)}=e^{2\pi}\approx e^{6.2832}\approx403.429\approx403.429\)

Answer:

\(h(\frac{1}{2}) = 0.368\)
\(h(1.5) = 0.050\)
\(h(-1) = 7.389\)
\(h(-\pi) = 403.429\)