Question

an unknown metal in the lab weighs 48.1 grams. it absorbs 575 j of heat, causing a temperature change from 25°c to 75°c. identify the unknown metal.

Explanation:

Step1: Use the heat - formula

The formula for heat \(Q = mc\Delta T\), where \(Q\) is the heat absorbed (\(Q = 575\space J\)), \(m\) is the mass (\(m=48.1\space g\)), \(c\) is the specific heat capacity, and \(\Delta T=T_{2}-T_{1}\) (\(\Delta T = 75 - 25=50^{\circ}C\)).
We can solve for \(c\) by re - arranging the formula: \(c=\frac{Q}{m\Delta T}\).

Step2: Substitute the values

Substitute \(Q = 575\space J\), \(m = 48.1\space g\), and \(\Delta T=50^{\circ}C\) into the formula:
\(c=\frac{575}{48.1\times50}\)
First, calculate \(48.1\times50 = 2405\).
Then \(c=\frac{575}{2405}\approx0.239\space J/(g\cdot^{\circ}C)\)

Answer:

Ag