Question

under the best conditions, a sprout has a 40% probability of blooming. if two sprouts are selected at random, what is the probability that both will bloom, under the best conditions? 16 percent 24 percent 40 percent 80 percent

Explanation:

Step1: Identify probabilities of individual events

The probability of one sprout blooming is $P_1 = 40\%=0.4$. Since the events of the two sprouts blooming are independent, the probability of the second sprout blooming is also $P_2 = 0.4$.

Step2: Use the multiplication - rule for independent events

For independent events $A$ and $B$, the probability of both $A$ and $B$ occurring is $P(A\cap B)=P(A)\times P(B)$. Here, the probability that both sprouts bloom is $P = P_1\times P_2$.
$P=0.4\times0.4 = 0.16$.

Step3: Convert to percentage

To convert the decimal to a percentage, we multiply by 100. So $0.16\times100 = 16\%$.

Answer:

16 percent