Question

type coefficients in each blank to balance the chemical equation below:? n₂ +? h₂ →? nh₃ once the equation above is balanced, type in the number of each atom below: reactants atom amount n? h? products atom amount n? h?

Explanation:

Step1: Balance nitrogen atoms

Let the coefficient of \(N_2\) be \(a\), \(H_2\) be \(b\), and \(NH_3\) be \(c\). For nitrogen atoms: \(2a = c\).

Step2: Balance hydrogen atoms

For hydrogen atoms: \(2b=3c\). Let \(a = 1\), then \(c = 2\). Substitute \(c = 2\) into \(2b = 3c\), we get \(2b=3\times2\), so \(b = 3\).

Step3: Calculate atom amounts (reactants)

For reactants: \(N\) atoms: \(2\times1 = 2\); \(H\) atoms: \(2\times3=6\).

Step4: Calculate atom amounts (products)

For products: \(N\) atoms: \(1\times2 = 2\); \(H\) atoms: \(3\times2 = 6\).

Answer:

Coefficients: \(1N_2+3H_2
ightarrow2NH_3\)

Reactants:

Atom	Amount
\(H\)	\(6\)

Products:

Atom	Amount
\(H\)	\(6\)