Question

two water tanks are leaking water. the equation and the table each represent the gallons of water in the tank, y, as a function of time in minutes, x. how much water does tank a hold before it starts to leak? find the initial value. 900 gallons how much water does tank b hold before it starts to leak? find the initial value. gallons tank a: y = 900 - 11x tank b: minutes, x | water in tank (gal), y 0 | 985 1 | 975 2 | 965 3 | 955

Explanation:

Step1: Understand Initial Value

The initial value (water before leaking) occurs at \( x = 0 \) (time = 0 minutes).

Step2: Find Tank B's Initial Value

For Tank B, look at the table. When \( x = 0 \) (minutes), the water \( y \) is 985 gallons.

Answer:

985