Question

try these:
$\square ca+\square o_2\to\square cao$
$ca=$
$o=$
$ca=$
$o=$
$\square n_2+\square h_2\to\square nh_3$
$n=$
$h=$
$n=$
$h=$
$\square cu_2o+\square c\to\square cu+\square co_2$
$cu=$
$o=$
$c=$
$cu=$
$o=$
$c=$
$\square h_2o_2\to\square h_2o+\square o_2$
$h=$
$o=$
$h=$
$o=$

Explanation:

Step1: Balance the first equation

For \(2Ca + O_{2}
ightarrow2CaO\),

• Left - hand side: \(Ca = 2\), \(O=2\)
• Right - hand side: \(Ca = 2\), \(O = 2\)

Step2: Balance the second equation

For \(N_{2}+3H_{2}
ightarrow2NH_{3}\),

• Left - hand side: \(N = 2\), \(H=6\)
• Right - hand side: \(N = 2\), \(H = 6\)

Step3: Balance the third equation

For \(2Cu_{2}O + C
ightarrow4Cu+CO_{2}\),

• Left - hand side: \(Cu = 4\), \(O = 2\), \(C = 1\)
• Right - hand side: \(Cu = 4\), \(O = 2\), \(C = 1\)

Step4: Balance the fourth equation

For \(2H_{2}O_{2}
ightarrow2H_{2}O + O_{2}\),

• Left - hand side: \(H = 4\), \(O = 4\)
• Right - hand side: \(H = 4\), \(O = 4\)

Answer:

1. \(2Ca + O_{2}

ightarrow2CaO\) (Left: \(Ca = 2\), \(O = 2\); Right: \(Ca = 2\), \(O = 2\))

1. \(N_{2}+3H_{2}

ightarrow2NH_{3}\) (Left: \(N = 2\), \(H = 6\); Right: \(N = 2\), \(H = 6\))

1. \(2Cu_{2}O + C

ightarrow4Cu+CO_{2}\) (Left: \(Cu = 4\), \(O = 2\), \(C = 1\); Right: \(Cu = 4\), \(O = 2\), \(C = 1\))

1. \(2H_{2}O_{2}

ightarrow2H_{2}O + O_{2}\) (Left: \(H = 4\), \(O = 4\); Right: \(H = 4\), \(O = 4\))