Question

6.4 trinomials where a does n
(1 point)
factor:
$3x^2 - 3x - 18 = \square$
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Explanation:

Step1: Factor out the GCF

The greatest common factor of $3x^2$, $-3x$, and $-18$ is 3.
$3x^2 - 3x - 18 = 3(x^2 - x - 6)$

Step2: Factor the quadratic trinomial

Find two numbers that multiply to $-6$ and add to $-1$: $-3$ and $2$.
$x^2 - x - 6 = (x - 3)(x + 2)$

Step3: Combine results

Substitute back the factored quadratic into the expression.
$3(x - 3)(x + 2)$

Answer:

$3(x - 3)(x + 2)$