Question

6.4 trinomials where a does not equal
(1 point)

factor:

14x⁴ + 5x² − 1 =

preview my answers submit answers
you have attempted this problem 0 times.
you have unlimited attempts remaining.
email instructor

Explanation:

Step1: Let \( y = x^{2} \)

The trinomial \( 14x^{4}+5x^{2}-1 \) becomes \( 14y^{2}+5y - 1 \)

Step2: Factor \( 14y^{2}+5y - 1 \)

We need to find two numbers \( m \) and \( n \) such that \( m\times n=14\times(- 1)=-14 \) and \( m + n=5 \). The numbers are \( 7 \) and \( - 2 \)

$$
LATEXBLOCK0
$$

Step3: Substitute back \( y = x^{2} \)

\((2x^{2}+1)(7x^{2}-1)\)

Answer:

\((2x^{2}+1)(7x^{2}-1)\)