Question

there are 4 moles of a gas at a pressure of 5.6 atm and a volume of 12 liters, what is the temperature?
p × v = n × r × t
r = 0.0821
a 204.6 c
b 488 k
c 22.7 k
d 204.6 k

Explanation:

Step1: Rearrange the ideal gas law formula

From \(PV = nRT\), we can solve for \(T\) as \(T=\frac{PV}{nR}\).

Step2: Substitute the given values

Given \(P = 5.6\space atm\), \(V=12\space L\), \(n = 4\space mol\), and \(R = 0.0821\space L\cdot atm/(mol\cdot K)\).
Substitute into the formula: \(T=\frac{5.6\times12}{4\times0.0821}\).
First calculate the numerator \(5.6\times12 = 67.2\), and the denominator \(4\times0.0821=0.3284\).
Then \(T=\frac{67.2}{0.3284}\approx204.6\space K\).

Answer:

D. 204.6 K