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theo and chey bought twice as many pounds of strawberries than pounds o…

Question

theo and chey bought twice as many pounds of strawberries than pounds of apples. they wrote two equations, where x is pounds of apples and y is pounds of strawberries:
$48 = 4x + 6y$
$y = 2x$
how many pounds of each fruit did they buy?

apples (lb), xstrawberries (lb), y

show or explain your thinking.

Explanation:

Step1: Substitute \( y = 2x \) into \( 48 = 4x + 6y \)

We know \( y = 2x \), so replace \( y \) in the first equation with \( 2x \). The equation becomes \( 48 = 4x + 6(2x) \).

Step2: Simplify and solve for \( x \)

First, calculate \( 6(2x)=12x \), so the equation is \( 48 = 4x + 12x \). Combine like terms: \( 4x + 12x = 16x \), so \( 48 = 16x \). Then divide both sides by 16: \( x=\frac{48}{16}=3 \).

Step3: Find \( y \) using \( y = 2x \)

Substitute \( x = 3 \) into \( y = 2x \), so \( y = 2\times3 = 6 \).

Answer:

Apples (lb), \( x \): 3
Strawberries (lb), \( y \): 6