QUESTION IMAGE
Question
the table gives a set of outcomes and their probabilities. let a be the event \the outcome is a divisor of 4\. find p(a).
| outcome | probability |
|---|---|
| 2 | 0.01 |
| 3 | 0.1 |
| 4 | 0.02 |
| 5 | 0.06 |
| 6 | 0.09 |
| 7 | 0.07 |
| 8 | 0.02 |
| 9 | 0.3 |
| 10 | 0.03 |
Step1: Identify the divisors of 4
The divisors of 4 are 1, 2, 4.
Step2: Sum their probabilities
$$P(A)=0.3 + 0.01+0.02$$
$$P(A)=0.33$$
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\(0.33\)