Question

1.sunil wants to earn an 88% in her chemistry class. she has one quiz left to take. on the first 5 quizzes, she received a 74%, 92%, 83%, 98%, 100%. what must she score on the 6th quiz to get the 88% she wants?

Explanation:

Step1: Calculate sum of first 5 quizzes

Sum = \( 74 + 92 + 83 + 98 + 100 \)
\( = 74 + 92 = 166 \); \( 166 + 83 = 249 \); \( 249 + 98 = 347 \); \( 347 + 100 = 447 \)

Step2: Let \( x \) be the 6th quiz score. Set up average formula

Average = \( \frac{\text{Total Sum}}{\text{Number of Quizzes}} \)
\( 88 = \frac{447 + x}{6} \)

Step3: Solve for \( x \)

Multiply both sides by 6: \( 88 \times 6 = 447 + x \)
\( 528 = 447 + x \)
Subtract 447: \( x = 528 - 447 = 81 \)

Answer:

81%