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the sum of the first and second of three consecutive even integers is 1…

Question

the sum of the first and second of three consecutive even integers is 142. find the three even integers. three even integers are . (use a comma to separate answers as needed.)

Explanation:

Step1: Let the first even integer be $x$.

The second consecutive even integer is $x + 2$, and the third is $x+4$.

Step2: Set up the equation.

The sum of the first and second is 142, so $x+(x + 2)=142$.

Step3: Simplify the left - hand side of the equation.

Combining like terms gives $2x+2 = 142$.

Step4: Solve for $x$.

Subtract 2 from both sides: $2x=142 - 2=140$. Then divide both sides by 2, so $x = 70$.

Step5: Find the other two even integers.

The second even integer is $x + 2=70+2 = 72$, and the third is $x + 4=70+4=74$.

Answer:

70, 72, 74