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Question
the sum of the first and second of three consecutive even integers is 142. find the three even integers. three even integers are . (use a comma to separate answers as needed.)
Step1: Let the first even integer be $x$.
The second consecutive even integer is $x + 2$, and the third is $x+4$.
Step2: Set up the equation.
The sum of the first and second is 142, so $x+(x + 2)=142$.
Step3: Simplify the left - hand side of the equation.
Combining like terms gives $2x+2 = 142$.
Step4: Solve for $x$.
Subtract 2 from both sides: $2x=142 - 2=140$. Then divide both sides by 2, so $x = 70$.
Step5: Find the other two even integers.
The second even integer is $x + 2=70+2 = 72$, and the third is $x + 4=70+4=74$.
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70, 72, 74