Question

sulfuryl chloride is a substance used to make chemicals for killing insects. it breaks down over time into sulfur dioxide and chlorine gas. consider the following reaction: some amount of sulfuryl chloride (so₂cl₂) breaks down to produce 6 molecules of sulfur dioxide (so₂) and 6 molecules of chlorine (cl₂). complete the table below. chemical element | number of atoms in the reaction o | s | cl | during this reaction, how many molecules of sulfuryl chloride (so₂cl₂) react?

Explanation:

Part 1: Completing the table (atoms count)

For Oxygen (O):

Step1: Determine O atoms from products

Each \( \text{SO}_2 \) has 2 O atoms. There are 6 \( \text{SO}_2 \) molecules. So O atoms from \( \text{SO}_2 \): \( 6 \times 2 = 12 \). Chlorine gas (\( \text{Cl}_2 \)) has no O atoms. Total O atoms: \( 12 \).

For Sulfur (S):

Each \( \text{SO}_2 \) has 1 S atom. 6 \( \text{SO}_2 \) molecules: \( 6 \times 1 = 6 \). Chlorine gas has no S atoms. Total S atoms: \( 6 \).

For Chlorine (Cl):

Each \( \text{Cl}_2 \) has 2 Cl atoms. 6 \( \text{Cl}_2 \) molecules: \( 6 \times 2 = 12 \). \( \text{SO}_2 \) has no Cl atoms. Total Cl atoms: \( 12 \).

Part 2: Molecules of \( \text{SO}_2\text{Cl}_2 \) reacted

Step1: Analyze the formula of \( \text{SO}_2\text{Cl}_2 \)

1 molecule of \( \text{SO}_2\text{Cl}_2 \) has 1 S, 2 O, and 2 Cl atoms.

Step2: Relate to product atoms

From products, we have 6 S, 12 O, 12 Cl atoms. For S: 6 S atoms mean \( \frac{6}{1} = 6 \) molecules of \( \text{SO}_2\text{Cl}_2 \) (since 1 molecule has 1 S). Checking O: 6 molecules × 2 O = 12 O (matches). Checking Cl: 6 molecules × 2 Cl = 12 Cl (matches). So 6 molecules react.

Answer:

(Table):

• O: \( 12 \)
• S: \( 6 \)
• Cl: \( 12 \)