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Question
students build four electromagnets and test them by picking up metal tacks. here are their partial results.
12 coils 4 tacks
24 coils 9 tacks
36 coils 13 tacks
48 coils ? tacks
which is the best prediction for the number of nails the electromagnet with 48 coils will pick up?
(1 point)
20 tacks
12 tacks
13 tacks
16 tacks
Step1: Analyze the pattern between coils and tacks
First, look at the differences in coils: from 12 to 24 (increase by 12), tacks from 4 to 9 (increase by 5); from 24 to 36 (increase by 12), tacks from 9 to 13 (increase by 4). The average increase in tacks per 12 - coil increase: $\frac{5 + 4}{2}=4.5$.
Step2: Predict for 48 coils
From 36 to 48 coils is another 12 - coil increase. So take the last tacks (13) and add approximately 4.5 (or see the trend: 4, 9, 13... the differences are 5, 4, so next difference around 4 - 5? Wait, 12 coils: 4; 24 coils: 9 (4 + 5); 36 coils: 13 (9 + 4); 48 coils: 13 + 5? Wait, maybe linear approximation. Let's list the number of coils (x) and tacks (y): (12,4), (24,9), (36,13). The slope between (12,4) and (24,9) is $\frac{9 - 4}{24 - 12}=\frac{5}{12}\approx0.4167$. Between (24,9) and (36,13): $\frac{13 - 9}{36 - 24}=\frac{4}{12}=\frac{1}{3}\approx0.333$. The average slope is $\frac{0.4167+0.333}{2}\approx0.375$. Now, for x = 48, using the first point (12,4): $y - 4 = 0.375\times(48 - 12)$; $y - 4 = 0.375\times36$; $y - 4 = 13.5$; $y = 17.5$. But looking at the options, 16 or 20? Wait, the differences: 12→24: +12 coils, +5 tacks; 24→36: +12 coils, +4 tacks; 36→48: +12 coils, maybe +4 or 5? 13 + 4 = 17, 13 + 5 = 18. But the options are 20,12,13,16. Wait, maybe my initial approach is off. Wait, 12 coils: 4; 24 coils: 9 (almost double coils, tacks more than double? 42=8, but 9). 36 coils: 13 (43=12, 13 is close). 48 coils: 44=16? Wait, 121=12, tacks 4; 122=24, tacks 9 (close to 42 +1); 123=36, tacks 13 (43 +1); 124=48, tacks 44=16? Wait, 4, 9 (42 +1), 13 (43 +1), 17? No, 44=16. Wait the options have 16. Alternatively, the trend: 4, 9 (4 + 5), 13 (9 + 4), 17 (13 + 4) but 17 not an option. Wait the options are 20,12,13,16. Wait 12 coils: 4; 24:9 (increase 5); 36:13 (increase 4); 48:13 + 5 = 18? No. Wait maybe the question has a typo (nails vs tacks) but focus on tacks. Wait the options: 20 is too high? Wait 12→24: +12 coils, +5 tacks; 24→36: +12, +4; 36→48: +12, +5 (to make the increases 5,4,5). So 13 + 5 = 18, not an option. Wait maybe the intended pattern is linear with a better fit. Let's do linear regression. The x values: 12,24,36. y values:4,9,13. The mean of x: $\frac{12 + 24 + 36}{3}=24$. Mean of y: $\frac{4 + 9 + 13}{3}=8.666...$. The slope $m=\frac{\sum(x_i - \bar{x})(y_i - \bar{y})}{\sum(x_i - \bar{x})^2}$. For (12 - 24)(4 - 8.666)=(-12)(-4.666)=56; (24 - 24)(9 - 8.666)=0(0.333)=0; (36 - 24)(13 - 8.666)=(12)(4.333)=52. Sum numerator: 56 + 0 + 52 = 108. Sum denominator: $(-12)^2+0^2+12^2=144 + 0 + 144 = 288$. So $m=\frac{108}{288}=0.375$. Then the equation is $y - 8.666 = 0.375(x - 24)$. For x = 48: $y - 8.666 = 0.375(24)$; $y - 8.666 = 9$; $y = 17.666$, which is close to 16 or 20? Wait the options: 20,12,13,16. Wait 16 is closer? Wait no, maybe the question's trend is that as coils increase, tacks increase, and the differences are 5,4, so next difference 5? 13 + 5 = 18, not there. Wait maybe the options have a typo, but among the options, 16 is the closest to the linear prediction (17.66) or 20? Wait 12 coils: 4; 24:9 (4 + 5); 36:13 (9 + 4); 48:13 + 5 = 18 (not option). Wait the options: 20 is higher, 16 is lower. Wait maybe the intended answer is 16? Wait no, wait 12 to 24: +12 coils, +5 tacks; 24 to 36: +12, +4; 36 to 48: +12, +4 (so 13 + 4 = 17, not option). Wait the options are 20,12,13,16. 12 is less than 13, 13 is same as before, so eliminate. 20 is too high? Wait maybe the question's data is different. Wait 12 coils: 4 tacks; 24 coils: 9 (42 +1); 36 coils: 13 (4*3 +1); 48…
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16 tacks