Question

a student wants to check six websites. four of the websites are social and two are school - related. after checking just two sites, she has to leave for school.
what is the approximate probability that she checked a social website first, then a school - related website?
0.042
0.267
0.533
0.667

Explanation:

Step1: Calculate the probability of checking a social website first

The total number of websites is \(n = 6\), and the number of social websites is \(m_1=4\). The probability of checking a social website first is \(P_1=\frac{4}{6}=\frac{2}{3}\).

Step2: Calculate the probability of checking a school - related website second

After checking one social website, the number of remaining websites is \(n_2 = 5\), and the number of school - related websites is \(m_2 = 2\). The probability of checking a school - related website second is \(P_2=\frac{2}{5}\).

Step3: Calculate the combined probability

Since these are two independent events (the result of the first check affects the second check), the combined probability \(P = P_1\times P_2\). Substitute \(P_1=\frac{2}{3}\) and \(P_2=\frac{2}{5}\) into the formula: \(P=\frac{2}{3}\times\frac{2}{5}=\frac{4}{15}\approx0.267\).

Answer:

0.267