Question

storyline 1 exam
which arrangement of the following period 5 elements, from left to right, orders them with respect to their atomic size, from smallest to largest?
o in, rb, sb, sr, te
o te, sb, in, sr, rb
o rb, sr, in, sb, te
o in, sb, te, rb, sr

Explanation:

Atomic size decreases across a period from left to right in the periodic table. This is because as the atomic number increases, the number of protons in the nucleus increases, which attracts the electrons more strongly, pulling them closer to the nucleus. Among the given elements (In - Indium, Rb - Rubidium, Sb - Antimony, Sr - Strontium, Te - Tellurium) in Period 5, their atomic numbers are: Rb (37), Sr (38), In (49), Sb (51), Te (52). So, arranging them from smallest to largest atomic size (i.e., from right to left in the period) gives Te < Sb < In < Sr < Rb.

Answer:

Te, Sb, In, Sr, Rb (the second option in the given choices)