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statistics from frequency table to histogram 11/18/25 this is due by en…

Question

statistics
from frequency table to histogram 11/18/25
this is due by end of period
and is worth 1 exit ticket (3 pts) & 1 practice grade (10 pts) & up to 5 xp challenge points.
i want you to first make a frequency table using your paper airplane data.
if you dont have data (for whatever the reason) come get some data from me.
a
list the 30 data values here:
1 8 2 11 3 12 4 14 5 15 6 11 7 19 8 23 9 20 10 15
11 12 12 3 13 15 14 23 15 24 16 13 17 15 18 20 19 23 20 13
21 15 22 18 23 18 24 11 25 14 26 19 27 25 28 13 29 16 30 6
reminder of the steps
1 max throw = 25 min throw = 8
range → max - min = 17
2 how many intervals? lets use 5 for this
3 interval width = range / 5 = 3.4 round up → 3.5
4 lows → 1^st at minimum... each interval low = previous low + rounded width
5 highs → each interval ends right before next one begins;
each interval high = previous high + rounded width
b
6 frequencies - how many throw distances in each interval range
7 relative frequencies - frequency proportion out of the total number of throws (as fraction,
decimal to 3 places or percent with 1 decimal)
8 cumulative frequencies - frequency total up to and including each interval
c
on the back - create a histogram (bar graph for numerical data)
horizontal axis scale → from minimum value to maximum value
vertical axis scale → from 0 to highest interval frequency
:: one bar per interval for whatever the frequency
:: bars should have minimal space between them & be labeled with interval values
practice grade :: table = 5 points; histogram = 5 points
exit ticket grade :: 9 - 10 pts = 3/3 // 5 - 8 pts = 2/3 // 2 - 4 pts = 1/3 // 0 - 1 pts = 0/3

Explanation:

Step1: Identify the data

The data consists of 30 throw distances.

Step2: Calculate the range

MAX THROW = 25, MIN THROW = 6. RANGE = MAX - MIN = 25 - 6 = 19.

Step3: Determine the interval width

Using 5 intervals. INTERVAL WIDTH = RANGE / 5 = 19 / 5 = 3.8 (rounded up to 4).

Step4: Define the intervals

1st interval: 6 - 9.9
2nd interval: 10 - 13.9
3rd interval: 14 - 17.9
4th interval: 18 - 21.9
5th interval: 22 - 25.9

Step5: Count the frequencies

  • For 6 - 9.9: 2
  • For 10 - 13.9: 7
  • For 14 - 17.9: 10
  • For 18 - 21.9: 5
  • For 22 - 25.9: 6

Step6: Calculate the relative frequencies

  • 2 / 30 ≈ 0.067
  • 7 / 30 ≈ 0.233
  • 10 / 30 ≈ 0.333
  • 5 / 30 ≈ 0.167
  • 6 / 30 = 0.2

Step7: Calculate the cumulative frequencies

  • 2
  • 2 + 7 = 9
  • 9 + 10 = 19
  • 19 + 5 = 24
  • 24 + 6 = 30

Answer:

INTERVALS from Low to HighFrequenciesRelative FrequenciesCumulative Frequencies
10 - 13.970.2339
14 - 17.9100.33319
18 - 21.950.16724
22 - 25.960.230