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solving by substitution mr. martin’s math test, which is worth 100 poin…

Question

solving by substitution
mr. martin’s math test, which is worth 100 points, has 29 problems. each problem is worth either 5 points or 2 points.
let x be the number of questions worth 5 points and let y be the number of questions worth 2 points.
x + y = 29, 5x + 2y = 100
how many problems of each point value are on the test?
○ 10 problems worth 5 points and 25 problems worth 2 points
○ 14 problems worth 5 points and 15 problems worth 2 points
○ 16 problems worth 5 points and 13 problems worth 2 points
○ 15 problems worth 5 points and 13 problems worth 2 points

Explanation:

Step1: Solve the first equation for y

From \( x + y = 29 \), we can express \( y \) as \( y = 29 - x \).

Step2: Substitute y into the second equation

Substitute \( y = 29 - x \) into \( 5x + 2y = 100 \). We get \( 5x + 2(29 - x) = 100 \).

Step3: Simplify and solve for x

Expand the equation: \( 5x + 58 - 2x = 100 \). Combine like terms: \( 3x + 58 = 100 \). Subtract 58 from both sides: \( 3x = 42 \). Divide by 3: \( x = 14 \).

Step4: Find y

Substitute \( x = 14 \) into \( y = 29 - x \), so \( y = 29 - 14 = 15 \).

Answer:

B. 14 problems worth 5 points and 15 problems worth 2 points